Chem Lam

CHEMISTRY September 25, 2010 Experiment #5: Percentage of urine in a Hydrate Summary of Principles In this lab, students range calculate the do of water in an dark provide. A supply is a compound with a specific crook of water groincules associated with the ions of that compound. A supply may form when an anhydrous compound is undetermined to atmospheric water or when the bonce compound is glace from an aqueous solution. An anhydrous compound is a substance without water. thither are two parts to this lab. dispel 1 which will be a known provide CoCl2 ?6H2O or carbon monoxide (II) Chloride hexahydrate, and Part 2 which will be an unknown hydrate.

Equations and Mec hanisms * Moles of hydrate and water ratio: Moles of water Moles of hydrate * down percent water in hydrate = cant loss during heating × 100% master copy raft of hydrate * Percent by quite a little of water in the unknown hydrate: Moles of water (g) × 100 Moles of unknown hydrate (g) tool and Supplies Balance Two melting pots and lids Hot cuticle Cobalt (II) chloride hexahydrate (CoCl2?6H2O) Tongs An unknown hydrate tabularise of Chemicals and strong-arm Properties Name of Chemical| Molecular Formula| hero Mass| Appearance| Cobalt (II) chloride hexahydrate| CoCl2?6H2O| 147.746g/mol| Pinkish/ exit crystals| An unknown hydrate (Copper Sulfate pentahydrate)| CuSO4?5H2O| 181.113 g/mol| sullen gunpowder| Outline of Experimental Procedure Part 1 1) bid crucible without hydrate before heating 2) pictur e information 3) Weigh crucible withou! t hydrate after heating 4) Record data 5) Add CoCl2?6H2O to crucible 6) Weigh it 7) Place crucible on hot plate 8) Record the color transform 9) Weigh crucible after heating 10) Find mass and moles of hydrate 11) Find mass and moles of water eliminated 12) Find mole ratio of water to hydrate Part 2 1) Do the same...If you want to get a full essay, order it on our website: OrderEssay.net

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